You may have such an experience inside an elevator: When the elevator accelerates upwards, you weigh more than you actually do, and when the elevator decelerates, you weigh less. To explain this phenomenon, we have to apply Newton's Laws of Motion.
Suppose a person of weight
is standing on a weighting machine in an elevator (Fig. 6-4). The weighting
machine and the person interact with the action-reaction pair of force
and
as shown in figure. As discussed before,
does not form an action-reaction pair with
.
The weighting machine measures the force
(=
)
acting on it, but not the actual weight
of the person. It is interesting to see that
and
are not always the same. We shall analyze the problem in three different
cases.
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| Fig. 6-4 (Left) A man standing on a weighting machine in an elevator. (Right) Free body diagram of the man. |
Suppose the elevator is at rest or moving with constant
velocity (acceleration
).
By Newton's second law, the resultant force acting on the person is zero,
i.e.,
,
hence
,
i.e., the machine gives the true weight of the person. However, if the
elevator is accelerating upwards (
,
take upward direction as positive),
,
so
,
i.e., the machine gives a reading greater than the true weight of the
person. In other words, the person weighs more in the elevator!
Similarly, when the elevator decelerates (
),
![]()
so
and so the person weighs less in the elevator!
Flash
animation: Change in weight of a person inside an elevator
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Example
![]() |
|
| Fig. 6-5 Free body diagram of the student. |
A student of mass 40 kg is now standing on a weighting
machine in an elevator (Take
).
Solution :
The free body diagram of the student is shown in Fig. 6-5 (take upward direction as positive).
(upwards)
Apply
,
(upwards)
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